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Bing and Luuk are playing tennis. The game is in a tie, 30-30. The probability of Luuk winning a point (so for example, from 15 to 30, or 30 to 40) is equal to 6/10.

What is the probability that Bing wins the game?
First, we start with summing up the possible scenarios. Bing can win in three different scenarios:
  1. Bing gets two points in a row, $0.4*0.4$.
  2. Bing gets a point, then Luuk gets a point and then Bing wins via a deuce.
  3. Luuk gets a point, then Bing gets a point and then Bing wins via a deuce.
The whole (hard) trick in this question is to figure out how to handle the probability related to a deuce. It seems like the deuce can be a never ending summation of probabilities. However, the trick is to recognise that the deuce-situation is equal to when the game is 30-30. Therefore, the equations to solve this problem are as follows: \begin{equation}
P(Bing \; | \; 30-30) = 0.4*0.4 + 0.4*0.6*P(Bing \; | \; Deuce) + 0.6*0.4*P(Bing \; | \; Deuce)
\end{equation} \begin{equation}
P(Bing \; | \; 30-30) = 0.4*0.4 + 2*0.4*0.6*P(Bing \; | \; Deuce)
\end{equation} As stated above, the deuce-situation is equal to when the game is 30-30. \begin{equation}
P(Bing \; | \; 30-30) = 0.4*0.4 + 2*0.4*0.6*P(Bing \; | \; 30-30)
\end{equation} \begin{equation}
0.52*P(Bing \; | \; 30-30) = 0.16
\end{equation} \begin{equation}
P(Bing \; | \; 30-30) = 30.7\%
\end{equation}
Correct Answer: 0.307
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def two_sum(nums, target):
    seen = {}
    for i, n in enumerate(nums):
        if target - n in seen:
            return [seen[target - n], i]
        seen[n] = i
    return []

print(two_sum([2, 7, 11, 15], 9))  # [0, 1]
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